16-(x^2-2xy+y^2)=0

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Solution for 16-(x^2-2xy+y^2)=0 equation: 


Simplifying
16 + -1(x2 + -2xy + y2) = 0

Reorder the terms:
16 + -1(-2xy + x2 + y2) = 0
16 + (-2xy * -1 + x2 * -1 + y2 * -1) = 0
16 + (2xy + -1x2 + -1y2) = 0

Solving
16 + 2xy + -1x2 + -1y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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